Home

Problem Statement

Takahashi loves numbers divisible by $2$.

You are given a positive integer $N$. Among the integers between $1$ and $N$ (inclusive), find the one that can be divisible by $2$ for the most number of times. The solution is always unique.

Here, the number of times an integer can be divisible by $2$, is how many times the integer can be divided by $2$ without remainder.

For example,

• $6$ can be divided by $2$ once: $6$ -> $3$.
• $8$ can be divided by $2$ three times: $8$ -> $4$ -> $2$ -> $1$.
• $3$ can be divided by $2$ zero times.

Constraints

• $1 ≤ N ≤ 100$

Sample Input 1

7

Sample Output 1

4

$4$ can be divided by $2$ twice, which is the most number of times among $1$, $2$, ..., $7$.

Sample Input 2

32

Sample Output 2

32

Sample Input 3

1

Sample Output 3

1

Sample Input 4

100

Sample Output 4

64