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Score : $200$ points

### Problem Statement

It is November $18$ now in Japan. By the way, $11$ and $18$ are adjacent Lucas numbers.

You are given an integer $N$. Find the $N$-th Lucas number.

Here, the $i$-th Lucas number $L_i$ is defined as follows:

• $L_0=2$
• $L_1=1$
• $L_i=L_{i-1}+L_{i-2} (i≥2)$

### Constraints

• $1≤N≤86$
• It is guaranteed that the answer is less than $10^{18}$.
• $N$ is an integer.

### Input

Input is given from Standard Input in the following format:

$N$


### Output

Print the $N$-th Lucas number.

### Sample Input 1

5


### Sample Output 1

11

• $L_0=2$
• $L_1=1$
• $L_2=L_0+L_1=3$
• $L_3=L_1+L_2=4$
• $L_4=L_2+L_3=7$
• $L_5=L_3+L_4=11$

Thus, the $5$-th Lucas number is $11$.

### Sample Input 2

86


### Sample Output 2

939587134549734843