Score : $300$ points
Joisino is planning to open a shop in a shopping street.
Each of the five weekdays is divided into two periods, the morning and the evening. For each of those ten periods, a shop must be either open during the whole period, or closed during the whole period. Naturally, a shop must be open during at least one of those periods.
There are already $N$ stores in the street, numbered $1$ through $N$.
You are given information of the business hours of those shops, $F_{i,j,k}$. If $F_{i,j,k}=1$, Shop $i$ is open during Period $k$ on Day $j$ (this notation is explained below); if $F_{i,j,k}=0$, Shop $i$ is closed during that period. Here, the days of the week are denoted as follows. Monday: Day $1$, Tuesday: Day $2$, Wednesday: Day $3$, Thursday: Day $4$, Friday: Day $5$. Also, the morning is denoted as Period $1$, and the afternoon is denoted as Period $2$.
Let $c_i$ be the number of periods during which both Shop $i$ and Joisino's shop are open. Then, the profit of Joisino's shop will be $P_{1,c_1}+P_{2,c_2}+...+P_{N,c_N}$.
Find the maximum possible profit of Joisino's shop when she decides whether her shop is open during each period, making sure that it is open during at least one period.
Input is given from Standard Input in the following format:
$N$
$F_{1,1,1}$ $F_{1,1,2}$ $...$ $F_{1,5,1}$ $F_{1,5,2}$
$:$
$F_{N,1,1}$ $F_{N,1,2}$ $...$ $F_{N,5,1}$ $F_{N,5,2}$
$P_{1,0}$ $...$ $P_{1,10}$
$:$
$P_{N,0}$ $...$ $P_{N,10}$
Print the maximum possible profit of Joisino's shop.
1 1 1 0 1 0 0 0 1 0 1 3 4 5 6 7 8 9 -2 -3 4 -2
8
If her shop is open only during the periods when Shop $1$ is opened, the profit will be $8$, which is the maximum possible profit.
2 1 1 1 1 1 0 0 0 0 0 0 0 0 0 0 1 1 1 1 1 0 -2 -2 -2 -2 -2 -1 -1 -1 -1 -1 0 -2 -2 -2 -2 -2 -1 -1 -1 -1 -1
-2
Note that a shop must be open during at least one period, and the profit may be negative.
3 1 1 1 1 1 1 0 0 1 1 0 1 0 1 1 1 1 0 1 0 1 0 1 1 0 1 0 1 0 1 -8 6 -2 -8 -8 4 8 7 -6 2 2 -9 2 0 1 7 -5 0 -2 -6 5 5 6 -6 7 -9 6 -5 8 0 -9 -7 -7
23