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Score: $100$ points

### Problem Statement

In AtCoder Kingdom, Gregorian calendar is used, and dates are written in the "year-month-day" order, or the "month-day" order without the year.
For example, May $3$, $2018$ is written as $2018$-$5$-$3$, or $5$-$3$ without the year.

In this country, a date is called Takahashi when the month and the day are equal as numbers. For example, $5$-$5$ is Takahashi.
How many days from $2018$-$1$-$1$ through $2018$-$a$-$b$ are Takahashi?

### Constraints

• $a$ is an integer between $1$ and $12$ (inclusive).
• $b$ is an integer between $1$ and $31$ (inclusive).
• $2018$-$a$-$b$ is a valid date in Gregorian calendar.

### Input

Input is given from Standard Input in the following format:

$a$ $b$


### Output

Print the number of days from $2018$-$1$-$1$ through $2018$-$a$-$b$ that are Takahashi.

### Sample Input 1

5 5


### Sample Output 1

5


There are five days that are Takahashi: $1$-$1$, $2$-$2$, $3$-$3$, $4$-$4$ and $5$-$5$.

### Sample Input 2

2 1


### Sample Output 2

1


There is only one day that is Takahashi: $1$-$1$.

### Sample Input 3

11 30


### Sample Output 3

11


There are eleven days that are Takahashi: $1$-$1$, $2$-$2$, $3$-$3$, $4$-$4$, $5$-$5$, $6$-$6$, $7$-$7$, $8$-$8$, $9$-$9$, $10$-$10$ and $11$-$11$.