Score : $500$ points
Let us denote by $f(x, m)$ the remainder of the Euclidean division of $x$ by $m$.
Let $A$ be the sequence that is defined by the initial value $A_1=X$ and the recurrence relation $A_{n+1} = f(A_n^2, M)$. Find $\displaystyle{\sum_{i=1}^N A_i}$.
Input is given from Standard Input in the following format:
$N$ $X$ $M$
Print $\displaystyle{\sum_{i=1}^N A_i}$.
6 2 1001
1369
The sequence $A$ begins $2,4,16,256,471,620,\ldots$ Therefore, the answer is $2+4+16+256+471+620=1369$.
1000 2 16
6
The sequence $A$ begins $2,4,0,0,\ldots$ Therefore, the answer is $6$.
10000000000 10 99959
492443256176507