﻿ ARC101 D - Median of Medians - Atcoder

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Score : $700$ points

### Problem Statement

We will define the median of a sequence $b$ of length $M$, as follows:

• Let $b'$ be the sequence obtained by sorting $b$ in non-decreasing order. Then, the value of the $(M / 2 + 1)$-th element of $b'$ is the median of $b$. Here, $/$ is integer division, rounding down.

For example, the median of $(10, 30, 20)$ is $20$; the median of $(10, 30, 20, 40)$ is $30$; the median of $(10, 10, 10, 20, 30)$ is $10$.

Snuke comes up with the following problem.

You are given a sequence $a$ of length $N$. For each pair $(l, r)$ ($1 \leq l \leq r \leq N$), let $m_{l, r}$ be the median of the contiguous subsequence $(a_l, a_{l + 1}, ..., a_r)$ of $a$. We will list $m_{l, r}$ for all pairs $(l, r)$ to create a new sequence $m$. Find the median of $m$.

### Constraints

• $1 \leq N \leq 10^5$
• $a_i$ is an integer.
• $1 \leq a_i \leq 10^9$

### Input

Input is given from Standard Input in the following format:

$N$
$a_1$ $a_2$ $...$ $a_N$


### Output

Print the median of $m$.

### Sample Input 1

3
10 30 20


### Sample Output 1

30


The median of each contiguous subsequence of $a$ is as follows:

• The median of $(10)$ is $10$.
• The median of $(30)$ is $30$.
• The median of $(20)$ is $20$.
• The median of $(10, 30)$ is $30$.
• The median of $(30, 20)$ is $30$.
• The median of $(10, 30, 20)$ is $20$.

Thus, $m = (10, 30, 20, 30, 30, 20)$ and the median of $m$ is $30$.

### Sample Input 2

1
10


### Sample Output 2

10


### Sample Input 3

10
5 9 5 9 8 9 3 5 4 3


### Sample Output 3

8